-4b^2-4b-1=0

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Solution for -4b^2-4b-1=0 equation: 



-4b^2-4b-1=0

a = -4; b = -4; c = -1;
Δ = b2-4ac
Δ = -42-4·(-4)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{4}{-8}=-1/2$

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